Question
If the seven-digit number 5728p9 is exactly divisible by
11, then what is the value of (11 p), where p > 0?Solution
Given the number 5728p9, use the divisibility rule for 11: Odd positions sum 5+2+p=7+p Even positions sum 7+8+9=24 For divisibility by 11- Â 7+p-24=11 Solving, p = 6. Thus, 11-p =11-6 =5
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