Find the smallest 4-digit number which when divided by 10, 15, 20, 25, 30 leaves remainder 9.
According to the question, the smallest 4-digit number which when divided by 10, 15, 20, 25, and 30 leaves a remainder of 9. = (LCM of 10, 15, 20, 25, 30) K+9 = 300K+9 Putting K = 4, = 300x4+9 = 1209
