Question
which of the following pairs of non-zeroes values of p
and q make the 6-digit number 674pq0 divisible by both 3 and 11?Solution
According to the option- Option 1: p = 5 and q = 2 Sum of the digits = 6+7+4+5+2+0=24 (divisible by 3) Alternating sum=6-7+4-5+2-0=0 (divisible by 11) This option passes the divisibility tests for both 3 and 11.
More Divisibility rules Questions
45, ?, 84, 114, 151, 195
14, 20, 29, 44, 65, ?
28, 43, 73, 118, ?, 253
8, 15, 44, 175, 874, ?
16, 9, ?, 114.25, 750.625, 6396.3125
150 - 10 × ( 7 - 2)/4 × 8 = ?
...250, 279, 311, 349, 396, ?
What will come in place of the question mark (?) in the following series?
112, 116, 121, ?, 134, 142
18, 35, 68, 117, ?, 263Â
100 180 294 448 648 ?
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