Question
which of the following pairs of non-zeroes values of p
and q make the 6-digit number 674pq0 divisible by both 3 and 11?Solution
According to the option- Option 1: p = 5 and q = 2 Sum of the digits = 6+7+4+5+2+0=24 (divisible by 3) Alternating sum=6-7+4-5+2-0=0 (divisible by 11) This option passes the divisibility tests for both 3 and 11.
Find the value of 24 - 3
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? = 49.99² ÷ (1.98⁵ + 8.01 × 89.91) + 75.15% of (263.89 × 49.11)
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