Question
If 'x' is the lowest positive integer divisible by 14,
22 and 30, then find the second smallest positive integer which is divisible by all the three given numbers?Solution
Lowest positive integer divisible by 14, 22 and 30 = LCM (14, 22, 30) So, LCM of (14, 22, and 30) = 2¹ × 3¹ × 5¹ × 7¹ × 11¹ = 4620 Therefore, the next larger number which is divisible by all the three given numbers = 2 × 4620 = 9240
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