Question
If 'x' is the lowest positive integer divisible by 16,
18 and 20, then find the second smallest positive integer which is divisible by all the three given numbers?Solution
Lowest positive integer divisible by 16, 18 and 20 = LCM (16, 18, 20) So, LCM of (16, 18, and 20) = 2⁴ × 3² × 5¹ = 720 Therefore, the next larger number which is divisible by all the three given numbers = 2 × 720 = 1440
More Divisibility rules Questions
(560 ÷ 32) × (720 ÷ 48) = ?
∛857375 + ∛91125 = ? + √6889
? = √2704 ÷ (25% of 104) + 73
What will come in the place of question mark (?) in the given expression?
(5/8) × 1600 + (2400 ÷ 25) = ?
50 ÷ 2.5 × 64 + ? = 1520
[(√ 529) + 67] x 5 = ?
182 – 517 ÷ 11 - √361 = ?
In the question, two Quantities I and II are given. You have to solve both the Quantity to establish the correct relation between Quantity-I and Quantit...
(3/7) of 700 + 33(1/3)% of 339 - 69 =?
Relevant for Exams:
