Question
If 'x' is the lowest positive integer divisible by 16, 18 and 20, then find the second smallest positive integer which is divisible by all the three given numbers?
More Divisibility rules Questions
- Find the least 4-digit number which is when divided by 14, 18, and 35 leaves a remainder of 13 in each case.
- Find the least 4-digit number which is when divided by 12, 15, and 20 leaves a remainder of 7 in each case.
- When a number is divided by 23, the quotient obtained is 168, and the difference between the quotient and the remainder is 152. Determine the number.
- A number n when divided by 6, leaves a remainder of 3. What will be the remainder when (n² +5n+8) is divided by 6?
- Find the least 4-digit number which is when divided by 21, 28, and 36 leaves a remainder of 11 in each case.
- A six-digit number 23p7q6 is divisible by 24. Then the greatest possible value for (p + q) is:
- Find the least 4-digit number which is when divided by 16, 20, and 24 leaves a remainder of 9 in each case.
- How many divisors does the number 5040 have?
- An eight-digit number, 81x3y72 is divisible by 72. Find the maximum possible value of x + y.
- On dividing a certain number by 304, we get 43 as the remainder. If the same number is divided by 16, what will be the remainder?
Relevant for Exams:
Hey! Ask a query
Please enter email id
The email must be a valid email address.
Please enter Mobile Number
Please enter valid Mobile Number
Please enter your Doubt
Think You're Ready for RBI Grade B?
RBI Grade B 2026 Phase 1 Memory Based Paper
- 200 Questions with Detailed Solutions
- Section-wise Coverage (GA, English, Quant & Reasoning)