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    Question

    Find the least 4-digit number which is when divided by

    16, 20, and 24 leaves a remainder of 9 in each case.
    A 1209 Correct Answer Incorrect Answer
    B 1089 Correct Answer Incorrect Answer
    C 1449 Correct Answer Incorrect Answer
    D 1329 Correct Answer Incorrect Answer

    Solution

    Prime factorization of 16 = 2тБ┤ Prime factorization of 20 = 2┬▓ ├Ч 5 Prime factorization of 24 = 2┬│ ├Ч 3 LCM of (16, 20, 24) = 2тБ┤ ├Ч 3 ├Ч 5 = 240 Least 4-digit number divisible by 240 = 1,200 So, required number = 1200 + 9 = 1,209

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