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    Question

    A six-digit number 27p5q8 is divisible by 36. What is

    the greatest possible value for (p×q)?
    A 48 Correct Answer Incorrect Answer
    B 12 Correct Answer Incorrect Answer
    C 24 Correct Answer Incorrect Answer
    D 36 Correct Answer Incorrect Answer

    Solution

    27p5q8 the number must be divisible by both 4 and 9, as 36 is the product of these two numbers. As we know the divisibility rule of 4 and 9 so, take the maximum value of p and q from 1 to 9. p=6 q=8 the greatest possible value of p×q =6×8 =48.

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