Question
There are βxβ students in a class. Out of them
βyβ are girls. The number of boys is 4 more than the number of girls. The sum of weight and the average weight of the girls is 754 kg and 58 kg, respectively. If 4 students are selected for a quiz competition then what will be the probability that the number of boys and the number of girls are equal?Solution
Total number of students = x The number of girls in the class = y The number of boys in the class = (y+4) Therefore the number of girls, => y = 754/58 = 13 Total number of girls = 13 Total number of boys = (13 + 4) = 17 Total number of students = (13 + 17) = 30 Required Probability = (13C2 Γ 17C2)/ 30C4 => (26 Γ 136)/27405 = 3536/9135
2(3/4) of 2880 + 54% of 7520 - ? = 302
Find the value of the following expression:
372 ÷ 56 × 7 – 5 + 2
- What will come in place of (?), in the given expression.
(5Β³ + 3Β²) Γ 2 = ? (1225/25) - (192/96) + (50/5) = ?

What will come in the place of question mark (?) in the given expression?
(555 + 385 - 535) Γ· 15 X ? = 36 X 30
- What will come in place of (?), in the given expression.
75% of 640 β 20% of 150 = ? `(21 xx 51 + 54)/(9 xx 14 - 30 )` =?
95% of 830 - ? % of 2770 = 650