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    Question

    The greatest number that will divide 398, 437 and 5425

    leaving 7, 12 and 2 as remainders, respectively, is:
    A 11 Correct Answer Incorrect Answer
    B 15 Correct Answer Incorrect Answer
    C 17 Correct Answer Incorrect Answer
    D 19 Correct Answer Incorrect Answer

    Solution

    Deducting the remainders from numbers we get, 398 βˆ’ 7 = 391 437 βˆ’ 12 = 425 5425 βˆ’ 2 = 5423 Now, 391 = 17 Γ— 23 425 = 17 Γ— 52 5425 = 17 Γ— 11 Γ— 29 So, HCF of these numbers = 17 ∴ The greatest number is 17.

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