Question
If the 6-digit number 589y72 is completely divisible by
8, then the smallest integer in place of y will be:Solution
For a number to be divisible by 8, the last three digits must be divisible by 8. Here, the last three digits are *72. Let's evaluate the values for *: If y = 0: 072 ÷ 8 = 9 (divisible) • If y = 1: 172 ÷ 8 = 21.5 (not divisible) • If y = 2: 272 ÷ 8 = 34 (divisible) • If y = 3: 372 ÷ 8 = 46.5 (not divisible) The smallest value of that makes the number divisible by 8 is 0.
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