Question
Let βxβ be the least number divisible by 9, 12, 16,
18 and 20, and also βxβ is a perfect square. Find the remainder when βxβ is divided by 95.Solution
ATQ, LCM of 9, 12, 16, 18 and 20 = 720 Since, 720 = (2 Γ 2 Γ 2 Γ 2 Γ 3 Γ 3 Γ 5) To make it a perfect square, multiply by β5β. So, desired number = 720 Γ 5 = 3600 3600 Γ· 95 = 37 Γ 95 + 85 So, desired remainder = 85
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