Question
Let ‘x’ be the least number divisible by 9, 12, 16,
18 and 20, and also ‘x’ is a perfect square. Find the remainder when ‘x’ is divided by 95.Solution
ATQ, LCM of 9, 12, 16, 18 and 20 = 720 Since, 720 = (2 × 2 × 2 × 2 × 3 × 3 × 5) To make it a perfect square, multiply by ‘5’. So, desired number = 720 × 5 = 3600 3600 ÷ 95 = 37 × 95 + 85 So, desired remainder = 85
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