Question
If the difference of two numbers is 4 and the difference
of their squares is 56, then the larger number isSolution
Let the numbers be a and b, where a > b According to the question, a – b = 4 …...(i) a2 – b2 = 56 (a + b)(a – b) = 56 (a + b) = 56/(a - b) = 56/4 = 14 a + b = 14 ……….(ii) Adding (i) & (ii), we get 2a = 18, a = 9
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