Question
Consider a three-digit number where the middle digit
(tens place) is 3. If the digits in the hundreds and ones places are swapped, the new number becomes 198 more than the original. Additionally, the sum of all the digits in the number is 13. Determine the original three-digit number.Solution
Let the digit at one's place and at hundredth place be 'y' and 'x' respectively. So, original number = (100x + 30 + y) [Since, 3 is at tens place] New number = (100y + 30 + x) ATQ, (100y + 30 + x) - (100x + 30 + y) = 198 Or, (99y - 99x) = 198 So, (y - x) = 2..........(I) Given, (y + x + 3) = 13 So, (y + x) = 10.............(II) On adding equation (I) and (II) , we get, y - x + y + x = 2 + 10 So, 'y' = (12/2) = 6 Using value of 'y' in equation (II) , we get, 'x' = 10 - 6 = 4 Therefore, original number = (100x + 30 + y) = 100 X 4 + 30 + 6 = 436Â
What will come in place of the question mark (?) in the following series?
1528, 1416, 1204, ?, 480, -32
143 Â Â Â Â 119Â Â Â Â 107Â Â Â Â 101Â Â Â Â Â 98Â Â Â Â ?
96 89 ? 90 94 91
...What value should come in the place of (?) in the following number series?
19, 235, 260, 324, 333, ?
What will come in place of the question mark (?) in the following series?
305...
In each of the following number series, one term is missing. Find the missing term.
3, 5, 20, 24, 144, 150, ?
1029, 1030, 1039, 1064, ?, 1194
75, 80, 95, ?, 155, 200
What will come in place of the question mark (?) in the following series?
1515, 184, ?, 455, 967, 624
7 29 61 ? 211 349
...
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