Question
In a 60-liter mixture of petrol
and diesel, the ratio of petrol to diesel is given as p:1. When 8 liters of diesel is added to the mixture, the amount of diesel becomes of the amount of petrol in the resulting mixture. Determine the value of p.Solution
ATQ, Let the initial quantity of diesel = ‘d’ L So, the initial quantity of petrol = (60 – d) L From the question: (d + 8) = (60 – d) × (125/300) 12d + 96 = 300 – 5d d = 12 The initial quantity of diesel = 12 L Quantity of petrol = 60 – 12 = 48 L So, value of p = 48/12 = 4
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