Question
A container βXβ holds 400 litres of a solution which
is 5/8th milk and the rest is water. 30% of this solution is poured into container βYβ, which already has 100 litres milk and 60 litres water. What will be the final ratio of milk to water in container βYβ?Solution
ATQ,
Quantity of milk in container βXβ = 400 Γ (5/8) = 250 litres
Quantity of water in container βXβ = 400 β 250 = 150 litres
Required ratio = {(0.30 Γ 250) + 100}:{(0.30 Γ 150) + 60} = (75 + 100):(45 + 60) = 175:105 = 5:3
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