Question
A mixture weighing 600 grams consists of sand and cement
in a ratio of 3:7. If an additional 20 grams of sand and 80 grams of cement are added to it, what will be the new ratio of cement to sand in the mixture?Solution
Quantity of sand in mixture = 3/10 X 600 = 180 grams Quantity of cement in mixture = 600 - 180 = 420 grams According to question, Desired ratio = (420 + 80) :(180 + 20) = 5:2 Hence, option b.
More Mixture Questions
31% of 3300 +659 = ?
?= √(4 × ∛(16 × √(4 × ∛(16 ×…… ∝)) ) )
60% of 500 + (729) 1/3 - ? = 72
∛857375 + ∛91125 = ? + √6889
1365 ÷ 15 + (? ÷ 5) = 62 × 3.5
Find the Value of
x= √(4 × ∛(16 × √(4 × ∛(16 ×…… ∝)) ) )
?2 = √20.25 × 10 + √16 + 32
36.76 + 2894.713 + 34965.11 =?
(2 ÷ 3) × (4 ÷ 12) × (? ÷ 10) × 45 × (1 ÷ 5) = (? ÷ 6) + (2 ÷ 5)
Relevant for Exams:
