Question
A 270 ml mixture contains juice and water in a ratio of
4:5. First, 20% of the mixture is removed and replaced with an equal amount of juice. This process is then repeated once more. What is the final quantity of juice in the mixture?Solution
Initial quantity of water = (5/9) × 270 = 150 ml
ATQ, Final quantity of water in the mixture = 150 × 0.8 × 0.8 = 96 ml
So, the final quantity of juice in the mixture = 270 – 96 = 174 ml
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