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      Question

      A 270 ml mixture contains juice and water in a ratio of

      4:5. First, 20% of the mixture is removed and replaced with an equal amount of juice. This process is then repeated once more. What is the final quantity of juice in the mixture?
      A 174 ml Correct Answer Incorrect Answer
      B 140 ml Correct Answer Incorrect Answer
      C 152 ml Correct Answer Incorrect Answer
      D 158 ml Correct Answer Incorrect Answer

      Solution

      Initial quantity of water = (5/9) Γ— 270 = 150 ml

      ATQ, Final quantity of water in the mixture = 150 Γ— 0.8 Γ— 0.8 = 96 ml

      So, the final quantity of juice in the mixture = 270 – 96 = 174 ml

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