Question
In a mixture of 144 litres (milk + water), the quantity
of milk is 40% greater than that of water. After 2P litres of the mixture is removed, the quantity of water remaining in the mixture is reduced to (P + 5) litres. Determine P% of the initial quantity of water in the mixture.Solution
Let the initial quantity of water be '5b' litres. So, initial quantity of milk = 1.4 X 5b = '7b' litres Now, 5b + 7b = 144 Or, 12b = 144 Or, 'b' = 12 ATQ, 5b - {(5/12) X 2P} = P + 5 Or, (5 X 12) - (5P/6) = P + 5 Or, P + (5P/6) = 60 - 5 Or, (11P/6) = 55 So, 'P' = 30 Therefore, required value = 0.3 X 5b = 0.3 X 5 X 12 = 18
15.99% of 549.99 ÷ 11.17 = ? ÷ 20.15
74.91% of 639.95 – 599.98% of 45 + 119.987 = ?
(4.88 × 5.76)2 - ?2 = 39.89 × 19.86
- What approximate value will come in place of the question mark (?) in the following question? (Note: You are not expected to calculate the exact value.)
- What approximate value will come in place of the question mark (?) in the following question? (Note: You are not expected to calculate the exactvalue.)
(1800.23 ÷ 29.98) + (816.32 ÷ 23.9) + 1634.11 = ?
1449.98 ÷ 50.48 × 10.12 = ? × 2.16
36.05 × 5.02 + 12.052 = ? + 9.09 × 4.04Â
(31.9)3 + (34.021)² - (16.11)3 - (42.98)² = ?