Question
In a mixture of 144 litres (milk + water), the quantity
of milk is 40% greater than that of water. After 2P litres of the mixture is removed, the quantity of water remaining in the mixture is reduced to (P + 5) litres. Determine P% of the initial quantity of water in the mixture.Solution
Let the initial quantity of water be '5b' litres. So, initial quantity of milk = 1.4 X 5b = '7b' litres Now, 5b + 7b = 144 Or, 12b = 144 Or, 'b' = 12 ATQ, 5b - {(5/12) X 2P} = P + 5 Or, (5 X 12) - (5P/6) = P + 5 Or, P + (5P/6) = 60 - 5 Or, (11P/6) = 55 So, 'P' = 30 Therefore, required value = 0.3 X 5b = 0.3 X 5 X 12 = 18
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