Question
If a pole of 54m height casts a shadow of 18`sqrt(3)` m long on the ground. Then the Sun’s angle of elevation at that instant is
In ∆ ABC tanθ= AB/BC = 54/(18√3) tanθ= 3/√3 = √3 tanθ= tan(60˚) θ = 60˚More Height and Distance Questions
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