πŸ“’ Too many exams? Don’t know which one suits you best? Book Your Free Expert πŸ‘‰ call Now!

    ⚑ Month End Offer - Flat 52% Off On All Courses! Enroll Now ⚑
    00:00:00 AM Left

    Question

    There is a 12 m tall hoarding pole on the top of a

    building. A person at some distance from the building, observes that the angle of elevation to the top of the hoarding pole from that point is the same as the angle of elevation to the bottom of the hoarding pole if he moves 4 √ 3 m closer to the building. What is the angle of elevation that the person is seeing?
    A 30Β° Correct Answer Incorrect Answer
    B 90Β° Correct Answer Incorrect Answer
    C 45Β° Correct Answer Incorrect Answer
    D 60Β° Correct Answer Incorrect Answer

    Solution

    Let AB be the building of height ‘h’ and BC be the hoarding pole of height 12 m. Let θ be the angle of elevation as seen by the person at a distance of ‘x’ m and ‘x + 4 √ 3‘ m. In Δ DAB, tan θ = h/x (i) In Δ EAC, tan θ = (h + 12)/ (x + 4 √ 3) (ii) From (i) and (ii) h/x = (h + 12)/ (x + 4 √ 3) ⇒ hx + 4 √ 3h = hx +12x ⇒ h/x = 12/ 4 √ 3 = √ 3 ⇒ tan θ = h/x = √ 3 = tan 60° ⇒ θ = 60°

    Practice Next
    More Height and Distance Questions

    Relevant for Exams:

    ask-question