Question
Solution
Let the numerator and denominator be x and y respectively β x = y + 3 Fraction = x/y β (y + 3)/y When 5 is added to the numerator and 2 is subtracted from denominator, β (y + 3 + 5)/(y β 2) = 8/3 β (y + 8)/(y β 2) = 8/3 β 3y + 24 = 8y β 16 β 5y = 40 β y = 8 Fraction = (8 + 3)/8 β 11/8 Dividing the original fraction by (11/2), β (11/8)/(11/2) β (2/8) β 1/4
Solve the quadratic equations and determine the relation between x and y:
Equation 1: 103xΒ² - 470x + 367 = 0
Equation 2: 107yΒ² - 504y + 397 = 0
Solve the quadratic equations and determine the relation between x and y:
Equation 1: xΒ² - 36x + 288 = 0
Equation 2: yΒ² - 36y + 320 = 0
In the question, two equations I and II are given. You have to solve both the equations to establish the correct relation between x and y.
I. x
If βy1β and βy2β are the roots of quadratic equation 5y2Β β 25y + 15 = 0, then find the quadratic equation whose roots are β3y1οΏ½...
If 3x β 2y = 10 and xy = 11, the value of 27xΒ³ β 8yΒ³ is __________.
I. 2x² - 15x + 27 = 0
II. 2y² - 13y + 20 = 0
If x^2 - 7x + k = 0 has roots that are equal, what is the value of k?
Solve the quadratic equations and determine the relation between x and y:
Equation 1: xΒ² - 34x + 288 = 0
Equation 2: yΒ² - 29y + 210 = 0
I. 20x² - 93x + 108 = 0
II.72y² - 47y - 144 = 0
I. 20y² - 13y + 2 = 0
II. 6x² - 25x + 14 = 0
