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ATQ; Let the denominator be ‘x’ So, numerator = 3x + 4 ATQ; (3x + 4 – 15)/(x + 43) = 2/3 Or, 9x – 33 = 2x + 86 Or, 7x = 119 Or, x = 17 Desired difference = 3x + 4 – x = 2x + 4 = 2 × 17 + 4 = 38
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