Question
A fraction becomes 6/7 when 3 is
added to both its numerator and denominator. Similarly, it becomes 7/8 when 5 is added to both its numerator and denominator. Determine the original fraction.Solution
ATQ, Let the original fraction be (x/y). {(x + 3)/(y + 3)} = (6/7) Or, 7x + 21 = 6y + 18 Or, 6y β 7x = 3 -------- (I) Also, {(x + 5)/(y + 5)} = (7/8) Or, 8x + 40 = 7y + 35 Or, 7y β 8x = 5 --------- (II) Equation (I) Γ 7 - Equation (II) Γ 6, we get 42y β 49x β 42y + 48x = 21 β 30 Or, x = 9 Putting βxβ in equation (I), we get y = (3 + 7 Γ 9)/6 = 11 so, the fraction = (9/11)
What will come in the place of question mark (?) in the given expression?
? = (27 Γ 13) β 26% of (412 β 92 )
- 60% of 180 β 30% of 60 = 15% of ?
- What will come in the place of question mark (?) in the given expression?
(120 - ?) Γ· 2 + 35 = 86 - 11 125% of 80 – 6 × 4 = ? × 13 – 54
Β β256 * 4 β 30% of 190 + ? = 110% of 220
162 Γ· [51 β {29 β (9 β 6Μ Μ +Μ Μ 7Μ )}]=?
`2(1/3)` + `4(1/4)` + `4(2/3)` + `8(7/6)` + ? = `4(3/5)xx4(1/2)`
...What will come in the place of question mark (?) in the given expression?
(5/8) Γ 1600 + (2400 Γ· 25) = ?Β
What is the value of βxβ if x% of 720 added to {2160 Γ· x of 20} Γ 2 gives 180?
Find the value of 16 X [(8 - 5) of 12 Γ· 4].
