Question
(I) 10x2 - 7x + 1 = 0 (II) 35y2 -
12y + 1 =0 In the following questions two equations numbered I and II are given. You have to solve both the equations. Give answer if;Solution
1. 10x2 - 7x + 1 = 0 or 10x2 - 5x - 2x + 1 = 0 (2x - 1) (5x - 1) = 0 or x = 1/2 , 1/5 2. 35y2 -12 y + 1 = 0 or 35y2 -7 y - 5y+ 1 = 0 (5y - 1)(7y – 1) = 0, or y =1/5 , 1/7 Hence, x ≥ y
(22 × 52 ) + 4 × 6 = ? - √324
What should come in place of (?) question mark in the given expression.
 (25% of 320) + (3/8 of 400) − 30 = ?
(5832)1/3  × 10.11 × 11.97 ÷ 16.32 = ? + 45.022
82% of 400 + √(?) = 130% of 600 - 85% of 400
If (x + 1/x) = 5, then value of x3 + 1/x3 is:
Simplify: (1 ÷ 0.08)
What should come in place of (?) question mark in the given expression.
{ (144 ÷ 12) × 5 } − (18 ÷ 3) = ?
Simplify the following expressions and choose the correct option.
(3/4 of 256) + (2/5 of 150) - (72 ÷ 7)
464 + 181 +? = (154 × 25) - (15) 2 Â
15% of 1800 + 22 = ?Â
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