Question
Determine the remainder when equation 4a3 -
5a2 + 2a + 1 is divided by (4a - 3) .Solution
ATQ, 4a - 3 = 0 Or, 'a' = (3/4) Remainder = 4 × (3/4)3 - 5 × (3/4)2 + 2 × (3/4) + 1 = 4 × (27/64) - 5 × (9/16) + (6/4) + 1 = (27/16) - (45/16) + (6/4) + 1 = (27 - 45 + 24 + 16) ÷ 16 = (22/16) = (11/8)
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