Question
The expression of (cot θ + cosec θ −1) / (cot θ −
cosec θ+1) is equal toSolution
(Cotθ + Cosecθ – 1) / (Cotθ – Cosecθ + 1) we know that [ ∵ Cosec2θ – cot2θ = 1] => (Cotθ + Cosecθ – (Cosec2θ – cot2θ)) / (Cotθ – Cosecθ + 1) => (Cotθ + Cosecθ – (Cosecθ + cotθ) (Cosecθ - cotθ)) / (Cotθ – Cosecθ + 1) => (Cotθ + Cosecθ (1 – Cosecθ + cotθ)) / (Cotθ – Cosecθ + 1) => (Cotθ + Cosecθ) => (Cosθ / Sinθ) + (1 / Sinθ) = (Cosθ + 1) / (Sinθ)
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