Question
The Price of 1 litre pure milk is Rs 50. By adding some
water in it and selling the mixture at Rs 60 one gets 25% profit, then find the ratio of milk and water in the mixture?Solution
Cost price of 1 litre milk = Rs 50 Selling price of 1 litre mixture = Rs 60 Profit = 25% So cost price of mixture = 60 × 100/125 = Rs 48 The ratio of milk and water in mixture 
I. 3x2 – 17x + 10 = 0
II. y2 – 17y + 52 = 0
How many values of x and y satisfy the equation 2x + 4y = 8 & 3x + 6y = 10.
Find the roots of the equation 6p² – 5p – 6 = 0.
I. 22x² - 97x + 105 = 0
II. 35y² - 61y + 24 = 0
I. 40 x² - 93 x + 54 = 0
II. 30 y² - 61 y + 30 = 0
l. 3x2 + 17x + 24 = 0
II. 2y2 + 15y + 27 = 0
Equation 1: x² - 144x + 5184 = 0
Equation 2: y² - 130y + 4225 = 0
I. x2 – 10x + 21 = 0
II. y2 + 11y + 28 = 0
Solve the quadratic equations and determine the relation between x and y:
Equation 1: 103x² - 470x + 367 = 0
Equation 2: 107y² - 504y + 397 = 0
I. 8x² + 2x – 3 = 0
II. 6y² + 11y + 4 = 0
Relevant for Exams:
