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    Question

    Four years ago, the average age of A, B and C was 24

    years. At present, the ratio of the ages of A and B is 3 : 2, and C is 4 years older than A. What is the present age of B?
    A 27 yrs Correct Answer Incorrect Answer
    B 12 yrs Correct Answer Incorrect Answer
    C 20 yrs Correct Answer Incorrect Answer
    D 33 yrs Correct Answer Incorrect Answer
    E None of these Correct Answer Incorrect Answer

    Solution

    ATQ, Four years ago: Average age = 24 тЖТ sum = 24 ├Ч 3 = 72 Let present ages: A = a, B = b, C = c Then (a тАУ 4) + (b тАУ 4) + (c тАУ 4) = 72 тЗТ a + b + c тАУ 12 = 72 тЖТ a + b + c = 84 тАж(1) Given: a : b = 3 : 2 тЖТ a = 3k, b = 2k Also c = a + 4 = 3k + 4 From (1): 3k + 2k + (3k + 4) = 84 тЗТ 8k + 4 = 84 тЖТ 8k = 80 тЖТ k = 10 So BтАЩs present age = b = 2k = 20 years.

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