Question
Six years ago, a father was 4 times as old as his son.
Six years from now, the father will be 5/2 times as old as the son. What is the son’s present age?Solution
Let present age of son = x Let present age of father = y Six years ago: y - 6 = 4(x - 6) y - 6 = 4x - 24 y = 4x - 18 Six years hence: y + 6 = 5/2(x + 6) Substitute y = 4x - 18 4x - 18 + 6 = 5/2(x + 6) 4x - 12 = 5/2(x + 6) Multiply by 2: 8x - 24 = 5x + 30 3x = 54 x = 18 Son’s present age = 18 years
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