Question
At present, the ages of ‘T’ and ‘U’ are in the ratio 6:7. Eight years from now, the ratio of their ages will become 7:8. What was T’s age 10 years ago?
Solution
ATQ,
Let present ages of T and U be 6x and 7x.
ATQ:
(6x + 8)/(7x + 8) = 7/8
⇒ 8(6x + 8) = 7(7x + 8)
⇒ 48x + 64 = 49x + 56
⇒ x = 8
So, present age of T = 6x = 48 years
T’s age 10 years ago = 48 – 10 = 38 years
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