Question
At present, the ages of ‘T’ and ‘U’ are in the
ratio 6:7. Eight years from now, the ratio of their ages will become 7:8. What was T’s age 10 years ago?Solution
ATQ,
Let present ages of T and U be 6x and 7x.
ATQ:
(6x + 8)/(7x + 8) = 7/8
⇒ 8(6x + 8) = 7(7x + 8)
⇒ 48x + 64 = 49x + 56
⇒ x = 8
So, present age of T = 6x = 48 years
T’s age 10 years ago = 48 – 10 = 38 years
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45 45.5 47 49.5 53 ?
...24, 42, 60, ?, 96, 114
What will come in place of the question mark (?) in the following series?
1528, 1416, 1204, ?, 480, -32
4 11 22 ? 56 79 106
...- What will come in place of the question mark (?) in the following series?
6, 19, 45, ?, 136, 201 226 231 466 ? 5606 28031
1500 150 30 ? 3.6 1.8
42, 48, 60, 84, 132, ?
7, 176, ?, 378, 427, 452
...4 10 ? 62.5 156.25 390.625
...
