Question
The age of 'P' five years from now will be the same as
the age of 'Q' four years ago. Six years ago, the sum of the ages of 'P' and 'Q' was 27 years. Additionally, 'R' is three years older than 'P'. Based on this information, calculate the age of 'R' four years from now.Solution
Let the present age of 'P' and 'Q' be 'a' years and 'b' years respectively. So, a + 5 = b - 4 Or, b - a = 9 -------- (I) And, a - 6 + b - 6 = 27 Or, a + b = 39 ------- (II) On adding equation I and II, We get, b - a + a + b = 9 + 39 Or, 2b = 48 Or, 'b' = 24 On putting value of 'b' in equation I, We get, 24 - a = 9 Or, 'a' = 15 So, present age of 'R' = 15 + 3 = 18 years Therefore, age of 'R' 4 years hence from now = 18 + 4 = 22 yearsÂ
((99.9 - 20.9)² + (99.9 + 20.9)² )/(99.9 x 99.9 + 20.9 x 20.9) = ?
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