Question
A is 2 years older than B while C is 3 years younger
than B. The ratio of age of A, 6 years hence and age of B, 5 years ago is 5:4. What was age of C, 10 years ago?Solution
Let the present age of B be x years. A’s present age = (x + 2) years C’s present age = (x - 3) years According to question, => [(x + 2) + 6]/(x - 5) = 5/4 => x = 57 C’s age, 10 years ago = (57 - 3) – 10 = 44 years
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