Question
Six years ago, the age of P was twice the age of Q.
After 6 years from now, the age difference between P and Q will be 18 years. Find the present age of P.Solution
Let the present ages of P and Q be x and y years respectively.
x – 6 = 2(y – 6)
x + 6 – (y + 6) = 18
⇒ x – y = 18
From first equation:
x – 6 = 2y – 12
x = 2y – 6
Substitute in second:
2y – 6 – y = 18
y = 24
x = 2(24) – 6 = 42
Present age of P = 42 years
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II). G ≤ B
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