Question
Present age of ‘A’ is 40% more than that of ‘B’.
If 11 years hence from now, ‘B’ will be 5 years younger than ‘A’, then find the sum of present ages of ‘A’ and ‘B’.Solution
Let present age of ‘B’ be ‘x’ years Present age of ‘A’ = x × 1.40 = ‘1.40x’ years ATQ; (x + 11) + 5 = (1.40x + 11) Or, x + 16 = 1.40x + 11 Or, 5 = 0.40x Or, x = 12.5 So, present age of ‘B’ = 12.5 years And, present age of ‘A’ = 12.5 + 5 = 17.5 years Required sum = 12.5 + 17.5 = 30 years
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Conclusions:
I. R > V
II. W < S
III. T > W
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Conclusions:
I. A > N
II. U < N
III. S ≥ Q
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Conclusions: I. P ≤ M II. L > N
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Conclusions:
I). G ≥ C
II). D ≤ B
III). C ≥ D
Statement: T>U<V<X=C>S ;U<P ≥X
I. T < P
II. P > S