Question
Present age of ‘A’ is 40% more than that of ‘B’.
If 11 years hence from now, ‘B’ will be 5 years younger than ‘A’, then find the sum of present ages of ‘A’ and ‘B’.Solution
Let present age of ‘B’ be ‘x’ years Present age of ‘A’ = x × 1.40 = ‘1.40x’ years ATQ; (x + 11) + 5 = (1.40x + 11) Or, x + 16 = 1.40x + 11 Or, 5 = 0.40x Or, x = 12.5 So, present age of ‘B’ = 12.5 years And, present age of ‘A’ = 12.5 + 5 = 17.5 years Required sum = 12.5 + 17.5 = 30 years
15   8   9   15   32    ?    250.5
80    81.5    83.5     ?     89      92.5
...8      27       64      125     ?       343Â
...18, 21, 45, 138, 555, ?
135, 148, ?, 184, 207, 236
33Â Â Â 41Â Â Â 25Â Â Â 49Â Â Â 17Â Â Â Â ?
25   25   37.5   ?   328.125   1804.6875
120, 130, 145, 165, ?, 220
11    16    42    141    ?   2945   17700
...80, 116, 52, ?, 8, 204