Question
Present age of βAβ is 40% more than that of βBβ.
If 11 years hence from now, βBβ will be 5 years younger than βAβ, then find the sum of present ages of βAβ and βBβ.Solution
Let present age of βBβ be βxβ years Present age of βAβ = x Γ 1.40 = β1.40xβ years ATQ; (x + 11) + 5 = (1.40x + 11) Or, x + 16 = 1.40x + 11 Or, 5 = 0.40x Or, x = 12.5 So, present age of βBβ = 12.5 years And, present age of βAβ = 12.5 + 5 = 17.5 years Required sum = 12.5 + 17.5 = 30 years
480 Γ· 10 + 18 % of 160 + ? * 9 = 60 * β36
`(sqrt(960.87)xx9.932+sqrt(629.998)xx26.385)/(sqrt(1028.902)xx4.977)=?`
What approximate value will come in place of the question mark (?) in the following question? (Note: You are not expected to calculate the exact value.)...
What approximate value will come in place of the question mark (?) in the following question? (Note: You are not expected to calculate the exact value.)...
(2100.23 ÷ 34.98) + (864.32 ÷ 23.9) + 1854.11 =?
- 29.98% of 249.897 = ?Β² β (4.98)Β²
What is the area (in cmΒ²) of a square inscribed in a circle with a radius of 10β2 cm?
What approximate value will come in place of the question mark (?) in the following question? (Note: You are not expected to calculate the exact value.)...
What approximate value will replace the question mark (?) in the following?
29.99...
(363.89% of 224.98 β 319.86% of 134.94) Γ· ? = β(134.88 Γ· 15.25)