Question
Present age of βAβ is 40% more than that of βBβ.
If 11 years hence from now, βBβ will be 5 years younger than βAβ, then find the sum of present ages of βAβ and βBβ.Solution
Let present age of βBβ be βxβ years Present age of βAβ = x Γ 1.40 = β1.40xβ years ATQ; (x + 11) + 5 = (1.40x + 11) Or, x + 16 = 1.40x + 11 Or, 5 = 0.40x Or, x = 12.5 So, present age of βBβ = 12.5 years And, present age of βAβ = 12.5 + 5 = 17.5 years Required sum = 12.5 + 17.5 = 30 years
I. 2x2 β 19x + 45 = 0
II. y2 β 14y + 48 = 0
Solve the quadratic equations and determine the relation between x and y:
Equation 1: 37xΒ² - 172x + 135 = 0
Equation 2: 29yΒ² - 132y + ...
I. 3x2 β 17x + 10 = 0
II. y2 β 17y + 52 = 0
I.β(3x-17)+ x=15
II. Β y+ Β 135/y=24Β
Solve the quadratic equations and determine the relation between x and y:
Equation 1: xΒ² - 42x + 392 = 0
Equation 2: yΒ² - 46y + 480 = 0
I. 8x² + 2x – 3 = 0
II. 6y² + 11y + 4 = 0
Solve the quadratic equations and determine the relation between x and y:
Equation 1: xΒ² - 29x + 210 = 0
Equation 2: yΒ² - 27y + 182 = 0
Between what values of x is the expression 19x - 2x2Β - 35 positive?
Solve the equation:-Β xΒ² β 9x + 20 = 0,Β What is the larger root?
I.Β p2Β - 19p + 88 = 0Β Β Β
II. q2Β - 48q + 576 = 0