Question
Present age of βAβ is 40% more than that of βBβ.
If 11 years hence from now, βBβ will be 5 years younger than βAβ, then find the sum of present ages of βAβ and βBβ.Solution
Let present age of βBβ be βxβ years Present age of βAβ = x Γ 1.40 = β1.40xβ years ATQ; (x + 11) + 5 = (1.40x + 11) Or, x + 16 = 1.40x + 11 Or, 5 = 0.40x Or, x = 12.5 So, present age of βBβ = 12.5 years And, present age of βAβ = 12.5 + 5 = 17.5 years Required sum = 12.5 + 17.5 = 30 years
(2310.23 Γ· 32.98) + (1008.32 Γ· 23.9) + 1594.11 = ?
? Γ 32.91 β 847.95 Γ· β16.4 β 13.982 = β24.7 Γ 24.04
119.98% of 80.02 - 15.12 Γ 2.02 + 19.95 = ?
25.09 Γ (β15 + 19.83) = ? of 19.87 Γ· 4.03Β
What approximate value will come in place of the question mark (?) in the following question? (Note: You are not expected to calculate the exact value.)...
68.98 × 41.03 – (12.33)² + 15.78% of 8398.87 = ? – 40.22
? % of 759.96 + 932.99 = 1237.01
Β (3/5) of 3025 + (18Β² + 12Β²) = ? + 22.22% of 1125
(70.03 Γ· 3.03 Γ 12.02) Γ· 35.03 Γ 20.02 Γ 8.08 = ? Γ (9.09 2.02 β 1.01)Β
- What approximate value will come in place of the question mark (?) in the following question? (Note: You are not expected to calculate the exactvalue.)