Question
A is 3 years older than B while C is 4 years younger
than B. The ratio of age of A, 6 years hence and age of B, 4 years ago is 3:2. What was age of C, 10 years ago?Solution
Let the present age of B be x years. A’s present age = (x + 3) years C’s present age = (x - 4) years According to question, => [(x + 3) + 6]/(x -4) = 3/2 => x = 30 C’s age, 10 years ago = (30 - 4) – 10 = 16 years
(22 × 52 ) + 4 × 6 = ? - √324
What should come in place of (?) question mark in the given expression.
 (25% of 320) + (3/8 of 400) − 30 = ?
(5832)1/3  × 10.11 × 11.97 ÷ 16.32 = ? + 45.022
82% of 400 + √(?) = 130% of 600 - 85% of 400
If (x + 1/x) = 5, then value of x3 + 1/x3 is:
Simplify: (1 ÷ 0.08)
What should come in place of (?) question mark in the given expression.
{ (144 ÷ 12) × 5 } − (18 ÷ 3) = ?
Simplify the following expressions and choose the correct option.
(3/4 of 256) + (2/5 of 150) - (72 ÷ 7)
464 + 181 +? = (154 × 25) - (15) 2 Â
15% of 1800 + 22 = ?Â
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