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    Question

    Current age of β€˜A’ is 20% more than that of β€˜B’.

    5 years ago, the ratio of the ages of β€˜A’ and β€˜C’ was 5:6. If the total of current ages of β€˜B’ and β€˜C’ is 62 years, then what is the total of present ages of β€˜A’ and β€˜B’?
    A 55 yrs Correct Answer Incorrect Answer
    B 72 yrs Correct Answer Incorrect Answer
    C 25 yrs Correct Answer Incorrect Answer
    D 62 yrs Correct Answer Incorrect Answer
    E None of these Correct Answer Incorrect Answer

    Solution

    ATQ, Let the present age of β€˜B’ = β€˜5x’ years Then, present age of β€˜A’ = 5x Γ— 1.20 = β€˜6x’ years 5 years ago, age of β€˜A’ = (6x – 5) years 5 years ago, age of β€˜C’ = (6x – 5) Γ— (6/5) = {(36x – 30)/5} years So, present age of β€˜C’ = {(36x – 30)/5} + 5 = {(36x – 5)/5} years Sum of present ages of β€˜B’ and β€˜C’ = 5x + {(36x – 5)/5} = {(25x + 36x – 5)/5} = {(61x – 5)/5} years So, {(61x – 5)/5} = 62 Or, 61x – 5 = 310 Or, x = (310 + 5) Γ· 61 Or, x = 5 So, sum of present ages of β€˜A’ and β€˜B’ = 6x + 5x = 11x = 11 Γ— 5 = 55 years

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