Question
Current age of βAβ is 20% more than that of βBβ.
5 years ago, the ratio of the ages of βAβ and βCβ was 5:6. If the total of current ages of βBβ and βCβ is 62 years, then what is the total of present ages of βAβ and βBβ?Solution
ATQ, Let the present age of βBβ = β5xβ years Then, present age of βAβ = 5x Γ 1.20 = β6xβ years 5 years ago, age of βAβ = (6x β 5) years 5 years ago, age of βCβ = (6x β 5) Γ (6/5) = {(36x β 30)/5} years So, present age of βCβ = {(36x β 30)/5} + 5 = {(36x β 5)/5} years Sum of present ages of βBβ and βCβ = 5x + {(36x β 5)/5} = {(25x + 36x β 5)/5} = {(61x β 5)/5} years So, {(61x β 5)/5} = 62 Or, 61x β 5 = 310 Or, x = (310 + 5) Γ· 61 Or, x = 5 So, sum of present ages of βAβ and βBβ = 6x + 5x = 11x = 11 Γ 5 = 55 years
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