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ATQ,
Let the present age of the son and the father be 'x' years and '5x' years, respectively.
Then, present age of the mother = (5x - 5) years
So, x + 5x + (5x - 5) = 110
Or, 11x - 5 = 110
So, x = (110 + 5) ÷ 11 = 10
Present ages of the son and father are 10 years and 50 years, respectively.
For some 'y',
(10 + y) × 2 = (50 + y)
Or, 20 + 2y = 50 + y
So, y = 30
30 years hence from now, the father will be twice as old as the son
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