Question
The sum of the present ages of a mother and her daughter
is 52 years. Four years ago, the mother was three times as old as her daughter. What is the daughter’s present age?Solution
ATQ, Let present age of daughter = d Present age of mother = m Given: m + d = 52 ...(1) Four years ago: Mother’s age = m − 4 Daughter’s age = d − 4 Given: m − 4 = 3(d − 4) m − 4 = 3d − 12 m = 3d − 8 ...(2) From (1): m + d = 52 Substitute m from (2): (3d − 8) + d = 52 4d − 8 = 52 4d = 60 d = 15 So daughter’s present age = 15 years.
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