Question
Present age of βPβ is 60% more than that of βQβ.
8 years ago, βPβ was twice as old as βQβ. Find the present age of βQβ.Solution
Let the present age of βQβ be βxβ years
Therefore, present age of βPβ = 1.6x years
ATQ;
(1.6x β 8) = 2 Γ (x β 8)
Or, 1.6x β 8 = 2x β 16
Or, 8 = 0.4x
Or, x = 20
Therefore, present age of βQβ = 20 years
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