Question
If present age of ‘A’ is three times the age of
‘B’, 4 years ago from now and sum of their ages 3 years hence from now will be 42 years, then find the present age of ‘B’.Solution
Let present age of ‘B’ = ‘x’ years So, present age of ‘A’ = 3 × (x – 4) years ATQ, (x + 3) + {3(x – 4) + 3} = 42 Or, 4x – 6 = 42 Or, 4x = 48 Or, x = 12 So, present age of ‘B’ = 12 years
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