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      Question

      Present age of 'A' is four times more than the age of

      his son. If two years ago, their ages were in ratio 9:1, respectively, then find the present age of 'A'.
      A 25 years Correct Answer Incorrect Answer
      B 20 years Correct Answer Incorrect Answer
      C 35 years Correct Answer Incorrect Answer
      D 45 years Correct Answer Incorrect Answer

      Solution

      Let the present age of A's son be 'x' years. So, present age of 'A' = x * 5 = '5x' years ATQ; {(5x - 2)/(x - 2)} = (9/1) Or, 5x - 2 = 9 * (x - 2) Or, 5x - 2 = 9x - 18 Or, 16 = 4x So, x = 4 So, present age of 'A' = 5 * 4 = 20 years

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