Question
The ratio of ages of P and Q after 12 years will be 7:4.
If the present age of P is 150% more than the age of Q six years ago, find their present average age.Solution
Let ages of P and Q after 12 years be 7x and 4x respectively. So, present ages: P = 7x − 12, Q = 4x − 12. According to question: 7x − 12 = 2.50 × (4x − 18) Or, 7x − 12 = 10x − 45 Or, 3x = 33 So, x = 11. Present P = 7x − 12 = 77 − 12 = 65, Present Q = 4x − 12 = 44 − 12 = 32. Desired Average = (65 + 32)/2 = 48.5 years.
(18.31)2 – (13.68)2 + (2344.20 + 82.32) ÷ ? = 229.90
- What approximate value will come in place of the question mark (?) in the following question? (Note: You are not expected to calculate the exact value.)
24.01 X 24.99 - ?% of 599.96 = 14.92 X 8.12
20.11 × 6.98 + 21.03 × 6.12 – 37.95 + 92.9 × 5.02 =?
Direction: Solve the following expression and calculate the approximate value.
(5.78 + 3.12)² + 8.2² + 2 × 8.1 × (5.9 + 3.2)
...Find the approximate value of Question mark(?). No need to find the exact value.
(55.96 × 4.01) ÷ 7 + √(120.81) × 3 – 10% of 199.99 = ?<...
888.191 + 2.0001 X 7.961= ?
80.09 * √144.05+ ? * √224.87 = (2109.09 ÷ √1368.79) * 19.89
- 44.83% of 799.88 + (84.12 X 14.98 ÷ 62.87) = ?² + 55.65
The greatest number that will divide 398,436, and 542 leaving 7, 11, and 15 as remainders, respectively, is:
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