Present ages of 'Ajay' and 'Bheem' are in ratio 5:8,

Solution

ATQ, Let the Ajay, Bheem and Charu can be defined as 'A', 'B' and 'C' respectively. Then, the present ages of 'A' and 'B' be '5x' years and '8x' years. So, age of 'C' five years hence from now = (5x + 5) ÷ 0.75 Since, present age of 'C' is an integer, (x + 1) must be divisible by 3. (As 20 is not) So, possible values of 'x' = 2, 5, 8 and so on. At 'x' = 2, present age of 'C' = {20 X 3 ÷ 3} - 5 = 15 years And sum of ages of 'A' and 'B' = 5x + 8x = 13x = 13 X 2 = 26 years At 'x' = 5, present age of 'C' = {20 X 6 ÷ 3} - 5 = 35 years And sum of ages of 'A' and 'B' = 5x + 8x = 13x = 13 X 5 = 65 years At 'x' = 8, present age of 'C' = {20 X 9 ÷ 3} - 5 = 55 years And sum of ages of 'A' and 'B' = 5x + 8x = 13x = 13 X 8 = 104 years At 'x' = 11, present age of 'C' = {20 X 12 ÷ 3} - 5 = 75 years And sum of ages of 'A' and 'B' = 5x + 8x = 13x = 13 X 11 = 143 years Since, sum of ages of 'A' and 'B' must be less than 110, the maximum possible age of 'C' is attained at 'x' = 8. So, maximum present age of 'C' = 55 years