Question
Amit marked up an article of cost price Rs. 800 by
certain percent and then sold it at discount of 20%. He suffered a loss of 12% in the whole transaction. Find the mark up percentage.ÂSolution
Selling price of the article = 0.88 × 800 = Rs. 704 Marked price of the article = 704/0.80 = Rs. 880 Required percentage = {(880 – 704)/704} × 100 = 10%
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 cot 14˚  ...If (sin A + cos A) = √3 cos (90° - A), then find the value of cot A.
- If 2cos²A + 3sin²A = 13/5, then find the value of (sec²A - 1)
If sin (2x + 50) o = cos (2y - 50) o, such that, 0o < x + y < 90o, then find the value of tan(x + y) .
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If cos 2A = 1, then find cos A
What is the simplified value of the given expression?
3(sin² 50° + sin² 40°) + 6sin 30° - (3sec 60° + cot 45°)
Find the value of `1/2`  cosec 10  - `2/(cosec 70)`  ?
Find the maximum value of 20 sin A + 9 cos A.
- If sin (3A − 4B) = (1/2) and cos (A + B) = (√2/2), where 0° < A, B < 90°, then find the value of ‘A’.