Question
The sum of the present ages of two cousins is 54 years.
Eleven years ago, the older one was thrice as old as the younger one. What is the present age of the older cousin?Solution
Let Present age of younger cousin and older cousin be a and b years respectively. ⇒ a + b = 54 ----(1) Also, 11 years ago, ⇒ (b – 11) = 3(a – 11) ⇒ b – 11 = 3a – 33 ⇒ 3a – b = 22 ----(2) Adding equation (1) and (2), we get ⇒ 4a = 76 ⇒ a = 19 By equation (1), we have ⇒ 19 + b = 54 ⇒ b = 35 ∴ Present age of Older cousin is 35 years.
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Conclusions:
I. R > V
II. W < S
III. T > W
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Conclusions : I. D % Q I...
Statements: Q ≤ R < A; R ≥ N > S; S ≥ T > U
Conclusions:
I. A > N
II. U < N
III. S ≥ Q
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(i) M # P
(ii) O © T
(iii) N #...
Statement: L ≥ M ≤ R = S; M > N ≥ P
Conclusions: I. P ≤ M II. L > N
Statements:
A < B = C; D = E ≤ F ≤ G; E ≤ B
Conclusions:
I). G ≥ C
II). D ≤ B
III). C ≥ D
Statement: T>U<V<X=C>S ;U<P ≥X
I. T < P
II. P > S
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