Question
20 years ago, the age of βIβ was 50% more than
βJβ. If the sum of their present ages is 90 years, then find the present age of βIβ.Solution
ATQ,
Let the present ages of βIβ and βJβ be (x + 20) years and (y + 20) years, respectively.
ATQ;
x = 1.50 Γ y = 1.5y β¦β¦β¦β¦β¦β¦. (1)
Also, x + 20 + y + 20 = 90
Or, x + y = 50 β¦β¦β¦β¦β¦. (2)
Putting x = 1.5y from equation (1), we have
1.5y + y = 50
Or, 2.5y = 50
So, y = 50 Γ· 2.5 = 20
So, x = 50 β 20 = 30
Therefore, present age of βIβ = 30 + 20 = 50 years.
Simplify the following expressions and choose the correct option.
{[(13)Β² β (7)Β²] Γ· 12} Γ 4 = ?
(25)Β² Γ 4 Γ· 5 + (3)Β³ + 48=? + 425
?2 + 114 - 48 Γ· 2 Γ 5 = 163
182 + 10 Γ 12 - ? = 312
2/5 of 3/4 of 7/9 of 7200 = ?
If (3 Γ 144 β 252 Γ· 14) Γ· 18 = β1024 β x, then find the value of βxβ.
12.50% of 1440 - 17 × 51 + 721 =?
[(15)³ × (8)²] ÷ (90 × 6) = ?²
?2 - (40% of 240) = 25 X 5
Simplify: 48 Γ· 4 Γ 3 + 5 Γ (6 β 2)