Question
Present age of βAβ is 40% more than that of βBβ.
If 10 years hence from now, βBβ will be 4 years younger than βAβ, then find the sum of present ages of βAβ and βBβ.Solution
Let present age of βBβ be βxβ years Present age of βAβ = x Γ 1.40 = β1.40xβ years ATQ; (x + 10) + 4 = (1.40x + 10) Or, x + 14 = 1.40x + 10 Or, 4 = 0.40x Or, x = 10 So, present age of βBβ = 10 years And, present age of βAβ = 10 + 4 = 14 years Required sum = 10 + 14 = 24 years
112, 130, 155, 196, 254, 342
Find the wrong number in the given number series.
11, 20, 38, 78, 154, 310112, 236, 374, 546, 790, 1376
75, 450, 225, 1330, 675, 4050
Find the wrong number in the given number series.
8, 12, 23, 40, 66, 103
In each of the following number series, one term is wrong. Find the wrong term.
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15, 34, 13, 32, 11, 28
217Β Β Β Β 210Β Β Β Β Β 236Β Β Β Β Β 299Β Β Β Β Β 423Β Β Β Β 640
...- Find the wrong number in the given number series.
3, 6, 18, 72, 360, 2160 In each of the following number series, one term is wrong. Find the WRONG term.
6, 9, 15, 27, 53, 99, 195