Question
Present age of βAβ is 40% more than that of βBβ.
If 10 years hence from now, βBβ will be 4 years younger than βAβ, then find the sum of present ages of βAβ and βBβ.Solution
Let present age of βBβ be βxβ years Present age of βAβ = x Γ 1.40 = β1.40xβ years ATQ; (x + 10) + 4 = (1.40x + 10) Or, x + 14 = 1.40x + 10 Or, 4 = 0.40x Or, x = 10 So, present age of βBβ = 10 years And, present age of βAβ = 10 + 4 = 14 years Required sum = 10 + 14 = 24 years
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