Question
Present age of βAβ is 40% more than that of βBβ.
If 10 years hence from now, βBβ will be 4 years younger than βAβ, then find the sum of present ages of βAβ and βBβ.Solution
Let present age of βBβ be βxβ years Present age of βAβ = x Γ 1.40 = β1.40xβ years ATQ; (x + 10) + 4 = (1.40x + 10) Or, x + 14 = 1.40x + 10 Or, 4 = 0.40x Or, x = 10 So, present age of βBβ = 10 years And, present age of βAβ = 10 + 4 = 14 years Required sum = 10 + 14 = 24 years
What approximate value will come in place of the question mark (?) in the following question? (Note: You are not expected to calculate the exact value.)...
(24.98)2 = ?2Β + (14.99)2
- What approximate value will come in place of the question mark (?) in the following question? (Note: You are not expected to calculate the exact value.)
9.95% of 1299.99 + 19.95 Γ 17.05 - 299.99 = ?
6106.11 Γ· β? Γ 55.9 = 3976.21Β Β
79.79% of 299.87 - 54.67% of (39.982 - 9.822 ) = ? - 19.92 Γ 199.98
? % of 759.96 + 932.99 = 1237.01
8.15 of 124.95 Γ· 40.13 + 249.84 X 14.18 - β325 X 149.87 = ? X 10.85
– (8.002)³ + (30.001)² - (4.01)β΄ =?
24.98% of 1682 Γ (18.2659 Γ· 9.04965)(β4) = ?Β