Question
Present age of ‘A’ is 40% more than that of ‘B’.
If 10 years hence from now, ‘B’ will be 4 years younger than ‘A’, then find the sum of present ages of ‘A’ and ‘B’.Solution
Let present age of ‘B’ be ‘x’ years Present age of ‘A’ = x × 1.40 = ‘1.40x’ years ATQ; (x + 10) + 4 = (1.40x + 10) Or, x + 14 = 1.40x + 10 Or, 4 = 0.40x Or, x = 10 So, present age of ‘B’ = 10 years And, present age of ‘A’ = 10 + 4 = 14 years Required sum = 10 + 14 = 24 years
What will come in place of the question mark (?) in the following series?
75, 219, 388, ?, 809, 106516.12 × 15.94 + 654.92 – 344.83 = ?× 5.95
660, 653, 639, 618, 590, ?
120, 126, 138, 162, ?, 306
11          20          ?             64          112        192
...Find the missing term in the series:
2, 5, 11, 23, 47, ?
580 557 528 497 ? 419
17, 38, 123, 508, ?, 15426
What will come in place of the question mark (?) in the following series?
55, 176, 320, ?, 685, 910
161Â Â Â Â 173Â Â Â Â Â Â 191 Â Â Â Â Â Â 215Â Â Â Â Â Â 245 Â Â Â Â Â Â ?
...
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