Let present age of ‘B’ be ‘x’ years Present age of ‘A’ = x × 1.40 = ‘1.40x’ years ATQ; (x + 11) + 5 = (1.40x + 11) Or, x + 16 = 1.40x + 11 Or, 5 = 0.40x Or, x = 12.5 So, present age of ‘B’ = 12.5 years And, present age of ‘A’ = 12.5 + 5 = 17.5 years Required sum = 12.5 + 17.5 = 30 years
1885 ÷ 64.98 + 7.29 + ? = 69.09
(49 x ?) / 3.5 + 389 = 627
25% of 400 + 3 × 102 = ?2
15% of 2400 + (√ 484 – √ 256) = ?
√10000 x √8100 - (50)² = √(?) + (80)²
13.5% of (100 + ?) = 27
? = (22% of 25% of 60% of 3000) + 21
Train M, ‘x’ metres long crosses (x – 30) metres long platform in 22 seconds while train N having the length (x + 30) metres crosses the same plat...
24% of 450 - 18 of 4 = 20 + ?4