Question
Sum of the present ages of A, B, C and D is 68 years.
After 4 years ratio of their ages is 5:4:3:2. What is C’s present age?Solution
At present sum of age = 68 years After 4 years sum of age will be, => 5x + 4x + 3x + 2x = 68 + 4 × 4 => 14x = 68 + 16 => x = 84/14 => x = 6 C’s present age = 3x – 4 = 14 years
(22 × 52 ) + 4 × 6 = ? - √324
What should come in place of (?) question mark in the given expression.
 (25% of 320) + (3/8 of 400) − 30 = ?
(5832)1/3  × 10.11 × 11.97 ÷ 16.32 = ? + 45.022
82% of 400 + √(?) = 130% of 600 - 85% of 400
If (x + 1/x) = 5, then value of x3 + 1/x3 is:
Simplify: (1 ÷ 0.08)
What should come in place of (?) question mark in the given expression.
{ (144 ÷ 12) × 5 } − (18 ÷ 3) = ?
Simplify the following expressions and choose the correct option.
(3/4 of 256) + (2/5 of 150) - (72 ÷ 7)
464 + 181 +? = (154 × 25) - (15) 2 Â
15% of 1800 + 22 = ?Â
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